Independent Study to consolidate this week
Two-sample tests
Set up
If you have just opened RStudio you will want to load the tidyverse
package
Exercises
- 💻 Plant Biotech. Some plant biotechnologists are trying to increase the quantity of omega 3 fatty acids in Cannabis sativa. They have developed a genetically modified line using genes from Linum usitatissimum (linseed). They grow 50 wild type and fifty modified plants to maturity, collect the seeds and determine the amount of omega 3 fatty acids. The data are in csativa.txt. Do you think their modification has been successful?
Answer - don’t look until you have tried!
csativa <- read_table("data-raw/csativa.txt")
str(csativa)
# First realise that this is a two sample test. You have two independent samples
# - there are a total of 100 different plants and the values in one
# group have no relationship to the values in the other.
Answer - don’t look until you have tried!
# create a rough plot of the data
ggplot(data = csativa, aes(x = plant, y = omega)) +
geom_violin()
Answer - don’t look until you have tried!
# note the modified plants seem to have lower omega!
Answer - don’t look until you have tried!
# The data seem to be continuous so it is likely that a parametric test will be fine
# we will check the other assumptions after we have run the lm
# build the statistical model
mod <- lm(data = csativa, omega ~ plant)
# examine it
summary(mod)
# So there is a significant difference but you need to make sure you know the direction!
# Wild plants have a significantly higher omega 3 content (mean +/- s.e = 56.41 +/- 1.11)
# than modified plants (49.46 +/- 0.82)(t = 5.03; d.f. = 98; p < 0.0001).
Answer - don’t look until you have tried!
# let's check the assumptions
plot(mod, which = 1)
Answer - don’t look until you have tried!
# we're looking for the variance in the residuals to be the same in both groups.
# This looks OK. Maybe a bit higher in the wild plants (with the higher mean)
hist(mod$residuals)
Answer - don’t look until you have tried!
shapiro.test(mod$residuals)
# On balance the use of lm() is probably justifiable The variance isn't quite equal
# and the histogram looks a bit off normal but the normality test is NS and the
# effect (in the figure) is clear.
Answer - don’t look until you have tried!
# A figure
fig1 <- ggplot() +
geom_point(data = csativa, aes(x = plant, y = omega),
position = position_jitter(width = 0.1, height = 0),
colour = "gray50") +
geom_errorbar(data = csativa_summary,
aes(x = plant, ymin = mean - se, ymax = mean + se),
width = 0.3) +
geom_errorbar(data = csativa_summary,
aes(x = plant, ymin = mean, ymax = mean),
width = 0.2) +
scale_x_discrete(name = "Plant type", labels = c("GMO", "WT")) +
scale_y_continuous(name = "Amount of Omega 3 (units)",
expand = c(0, 0),
limits = c(0, 90)) +
annotate("segment", x = 1, xend = 2,
y = 80, yend = 80,
colour = "black") +
annotate("text", x = 1.5, y = 85,
label = expression(italic(p)~"< 0.001")) +
theme_classic()
# save figure to figures/csativa.png
ggsave("figures/csativa.png",
plot = fig1,
width = 3.5,
height = 3.5,
units = "in",
dpi = 300)